richjessica2002
richjessica2002
06-01-2019
Mathematics
contestada
please answer with explanation
Respuesta :
SFM19613
SFM19613
06-01-2019
[tex] - 1 \: \leqslant \: \cos( \alpha ) \: \leqslant \: 1[/tex]
[tex]y \: = \: \cos( \frac{x}{2} ) [/tex]
[tex] \cos( \alpha ) \: = \: - 1 \: = \: \cos( \frac{x}{2} ) [/tex]
[tex] \alpha \: = \: {\pi }^{ c} [/tex]
[tex] \frac{x}{2} \: = \: \pi[/tex]
[tex]x \: = \: 2\pi[/tex]
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