Area of Canvas Cloth required (A) = Curved/Lateral Surface Area of the Cone = [tex]\pi \: × \: rl[/tex]
A = πrl
r = 12 m
h = 3.5 m
[tex]l \: = \: \sqrt{ {r}^{2} \: + \: {h}^{2} } [/tex]
[tex]l \: = \: \sqrt{ {(12)}^{2} \: + \: {(3.5)}^{2} }[/tex]
[tex]l \: = \: \sqrt{144 \: + \: 12.25} \: = \: \sqrt{156.25} \: = \: 12.5[/tex]
l = 12.5 m
A = π × 12 m × 12.5 m
A ≈ 471.2389 m².
Hence, 471.2389 m² of Canvas is required to cover the heap.
