How many grams of N2 are produced from 100. g of NH3 in the following reaction? 4NH3(g) + 6NO(g) → 5N2(g) + 6H2O(l)
A) 165 g B) 132 g C) 125 g D) 206 g E) 7.35 g

Respuesta :

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Answers:

D) 206. g

Step-by-step explanation:

We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:  17.03                   28.02

          4NH₃ + 6NO ⟶ 5N₂ + 64H₂O

m/g:  100.

(1) Calculate the moles of NH₃

n = 100. g NH₃ ×1 mol NH₃/17.03 g NH₃

n = 5.872 mol NH₃

(2) Calculate the moles of N₂

The molar ratio is (5 mol N₂/4 mol NH₃)

n = 5.872 mol NH₃ × (5mol N₂/4 mol NH₃)

n = 7.340 mol

(3) Calculate the mass of N₂

Mass of N₂ = 7.340 mol N₂ × (28.02 g N₂/1 mol N₂)

Mass of N₂ = 206 g N₂