Answer: Option B ([tex]x=1[/tex]±[tex]i\sqrt{3}[/tex])
Step-by-step explanation:
1. To solve this problem you must use the Quadratic formula, which is used to solve quadratic equation. This formula is shown below:
[tex]x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}[/tex]
2. Make the equation equal to zero. So, you must rewrite it as following:
[tex]6x^{2}-12x+24=0[/tex]
3. Now, you must substitute values. Then, you have:
[tex]a=6\\b=-12\\c=24[/tex]
[tex]x=\frac{-(-12)+/-\sqrt{(-12)^{2}-4(6)(24)}}{2(6)}[/tex]
4. Then,you obtain the following result:
[tex]x=1[/tex]±[tex]i\sqrt{3}[/tex]
