Answer:
[tex]y=2x^2-44x+240[/tex]
Step-by-step explanation:
we are given a quadratic equation
Let's assume formula of vertex form of parabola as
[tex]y=a(x-h)^2+k[/tex]
where vertex is (h,k)
we are given
vertex =(11,-2)
so, h=11, k=-2
now, we can plug it
[tex]y=a(x-11)^2-2[/tex]
now, we are given zeros at x=10 and x=12
we know that zeros will be x=10 , y is 0
so, we can plug x=10 and y=0 and solve for 'a'
[tex]0=a(10-11)^2-2[/tex]
[tex]0=a-2[/tex]
[tex]a=2[/tex]
now, we can plug it back
and we get
[tex]y=2(x-11)^2-2[/tex]
so, we get quadratic equation as
[tex]y=2x^2-44x+240[/tex]
