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A 50 kg boy jumps off the back of a 4 kg skateboard moving forward. Find the skateboard’s velocity immediately after the boy jumps, assuming that the skateboard’s initial velocity is 5 m/s and the boy’s velocity when jumping off the back is 2.5 m/s in the forward direction.

Respuesta :

onyebuchinnaji

The final velocity of the skateboard is 36.25 m/s.

Conservation of linear momentum

The velocity of the skateboard can be determined by applying the principle of conservation of linear momentum.

u(m₁ + m₂) = m₁v₁ + m₂v₂

where;

  • v₂ is the final velocity of the skateboard
  • u is the initial velocity of the boy and skateboard
  • v₁ is the final velocity of the boy

5(50 + 4) = 50(2.5) + 4v₂

270 = 125 + 4v₂

145 = 4v₂

v₂ = 145/4

v₂ = 36.25 m/s

Thus, the final velocity of the skateboard is 36.25 m/s.

Learn  more about conservation of linear momentum here: https://brainly.com/question/7538238

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