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Two football players with mass 85 kg and 110 kg run directly toward each other with speeds 4 m/s and 7 m/s respectively. If they grab each other as they collide, what is the combined speed of the players just after the collision?

Respuesta :

remotecontrolbrain

Use the conservation of the momentum to answer this question:

[tex]m_1\vec v_1+m_2\vec v_2 = m\vec v\implies\\\vec v = \frac{m_1\vec v_1+m_2\vec v_2}{m_1+m_2}\\v = \frac{85kg\cdot 4 m/s+110kg\cdot (-7m/s)}{195kg}=-2.2\frac{m}{s}[/tex]

The resulting speed of the two bodies will be 2.2 m/s in the (original) direction of the overweight guy (110kg). Their brains not happy about the collision either.

onyebuchinnaji

The combined speed of the players after the collision is 2.21 m/s.

Conservation of linear momentum

The combined speed of the players after the collision is calculated by applying the principle of conservation of linear momentum.

m₁v₁ + m₂v₂ = v(m₁ + m₂)

(110 x 7) - (85 x 4) = v(110 + 85)

430 = v(195)

v = 430/195

v = 2.21 m/s

Thus, the combined speed of the players after the collision is 2.21 m/s.

Learn more about conservation of linear momentum here: https://brainly.com/question/7538238

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