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[tex]\displaystyle\\m(\sphericalangle JKM)=\frac{1}{2}m(\sphericalangle JKL)\\\\ \text{Correct answer is A}[/tex]

Answer:

Question 54a: Option A

Question 54b: Bisect <JKM

Question 54c: First, bisect the 60 degree angle to create a 30 degree angle. Next you bisect the 30 degree angle to create 15 degree angle.

Step-by-step explanation:

Question 54a: ray KM, is a bisector of <JKL, thus m<JKM is 1/2 of <JKL

Question 54b: Bisecting a angle the is half of another angle would create an angle that is one fourth of the overall angle.

Question 54c: Bisecting angles cuts them in half.

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