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What is the 10th term of the sequence 64, 16, 4,...?

a. 1/1024

b. 1/256

c. 1/4096

d. 1/496

Respuesta :

Each time we are dividing by 4.
Essentially, multiplying by 1/4.
Since we're multiplying, that makes this a geometric sequence!

So: Our first term is 64, and the common ratio is 1/4.
Let's plug that into the geometric sequence formula.

[tex]a_n=a_1(r)^{n-1}[/tex]

Where a_n = the value of the nth term
a_1 = the first term, and r = the common ratio

[tex]a_n=64(\frac14)^{n-1}[/tex]

Now that we have our equation, let's plug in 10 for n.
That way, we can solve to find [tex]a_{10}[/tex], the value of the 10th term.

[tex]a_{10}=64(\frac14)^{10-1}=\boxed{\frac{1}{4096}}[/tex]

the answer is C. 1/4096