Answer:
Probability that 2 jars drawn at random will contain less jam is 0.00886524822
Step-by-step explanation:
A jam manufacturer knows that in a box of 48 jars,5 will contain less jam than shown on the label. Now we have to find the probability that 2 jars drawn at random will contain less jam.
Given 5 jars contain less jam as shown on label. So 2 jars drawn at random from these 5 jars therefore number of ways or favourable outcome will be [tex]_{2}^{5}\textrm{C}[/tex]
Total no. of outcomes=[tex]_{2}^{48}\textrm{C}[/tex]
P(2 jars with less jam)=[tex]\frac{Favourable outcome}{Total outcomes}[/tex]
= [tex]\frac{_{2}^{5}\textrm{C}}{_{2}^{48}\textrm{C}}[/tex]
= [tex]\frac{\frac{5!}{2!3!}}{\frac{48!}{2!46!}}=\frac{5}{12(47)}=0.00886524822[/tex]
Hence, probability that 2 jars drawn at random will contain less jam is 0.00886524822