The resistance in a lightbulb with a voltage of 12V and a current of 0.15A is 80Ω
Hence, Option C. 80Ω is the correct answer.
Given the data in the question;
Voltage of the bulb; [tex]V = 12V[/tex]
Current; [tex]I = 0.15A[/tex]
Resistance; [tex]R = ?[/tex]
To find the Resistance in the bulb, we use the formula from Ohm's law.
Ohm's law states that for a conductor in a given state, the voltage across it is directly proportional to the current flowing through it, given that the temperature and other physical conditions remain constant.
So, from Ohm's law:
[tex]V = I\ *\ R\\[/tex]
Where R is the resistance, I is the current and V is the voltage.
We simply substitute our given values in the equation and find R
[tex]12V = 0.15A\ * \ R\\\\R = \frac{12V}{0.15A} \\\\[/tex]
R = 80Ω
The resistance in a lightbulb with a voltage of 12V and a current of 0.15A is 80Ω.
Hence, Option C. 80Ω is the correct answer.
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