Answer:The average acceleration of the sled is [tex]170.66 m/s^2[/tex]
Explanation:
Initial Velocity of the rocket ,u= 0 m/s
Final Velocity of the rocket ,v= [tex]7.660\times 10^{2} m/s[/tex]
Distance covered by the sled,s = [tex]1.719\times 10^{3} m[/tex]
[tex]v^2-u^2=2as[/tex] (Third equation of motion)
[tex](7.660\times 10^{2} m/s)^2-(0 m/s)^2=2a(1.719\times 10^{3} m)[/tex]
[tex]a=170.66 m/s^2[/tex]
The average acceleration of the sled is [tex]170.66 m/s^2[/tex]
