Answer: option B. 45°
Explanation:
A body thrown at an angle from horizontal undergoes a projectile motion. The maximum horizontal displacement means the maximum range covered. The range is given by:
[tex]R = \frac{v^2 sin 2\theta}{g}[/tex]
where v is the initial velocity, [tex]\theta[/tex] is angle of the projectile and g is the acceleration due to gravity.
For maximum range, sin 2θ = 1
2θ = sin⁻¹ 1 = 90°
θ = 90°/2 = 45°
Thus, the projectile undergoes maximum horizontal displacement at angle of 45°. Correct option is B.
