Respuesta :
[tex]3x + 2 \leqslant 5(x - 4) \\ 3x + 2 \leqslant 5x - 20 \\ 2 + 20 \leqslant 5x - 3x \\ 22 \leqslant 2x \\ \frac{22}{2} \leqslant x \\ 11 \leqslant x[/tex]
Answer:
x ≥ -11
ABOUT THIS ≤ INEQUALITY SIGN:
- Less than/Equal to
- No more than
- At Most
- Maximum of
3x + 2 ≤ 5(x - 4)
3x + 2 ≤ 5x - 20
-5x -5x
-2x + 2 ≤ -20
- 2 -2
-2x ≤ 22
-2 -2
x ≥ -11
Hope this helps you!!! :)