corinltm
contestada

A 70 kilogram mountaineer is standing on the summit of Mt. Everest. The distance between the mountaineer and the center of Earth is 6.39 × 10^6 meters. What is the magnitude of the force of gravity acting on the mountaineer? (The value of G is 6.673 × 10-11 newton meter2/kilogram2. The mass of Earth is 5.98 × 1024 kilograms.)
A. 90.5 newtons
B. 179 newtons
C. 648 newtons
D. 781 newtons

Respuesta :

Answer: 684 N

Explanation:

The force of gravity between two objects having mass is given by:

[tex]F=G\frac{Mm}{r^2}[/tex]

where, G is the gravitational constant, [tex]G= 6.673\times 10^{-11} Nm^2/kg^2[/tex], m is the mass of the man, [tex]m = 70 kg[/tex] and M is the mass of the Earth, [tex]M = 5.98 \times 10^{24} kg[/tex] and r is the distance between two masses, [tex]r = 6.39 \times 10^6 m[/tex]

[tex]\Rightarrow F = 6.673\times 10^{-11} Nm^2/kg^2\times \frac{5.98 \times 10^{24} kg \times 70 kg}{(6.39 \times 10^6 m)^2} = 684 N.[/tex]

Thus, the magnitude of the force of gravity acting on the mountaineer is 684 N.

answer is 684 newtons on plato, got 100 on the test :)