Respuesta :
Answer : The mass of Ni is, 80.346 g
Solution :
First we have to calculate the number of moles.
[tex]\text{Moles of }NO_2=\frac{\text{Mass of }NO_2}{\text{Molar mass of }NO_2}=\frac{63g}{46g/mole}=1.369moles[/tex]
Now we have to calculate the number of atoms of [tex]NO_2[/tex]
As 1 moles [tex]NO_2[/tex] contains [tex]6.022\times 10^{23}[/tex] number of molecules
So, 1.369 moles [tex]NO_2[/tex] contains [tex]1.369\times 6.022\times 10^{23}[/tex] number of molecules
One [tex]NO_2[/tex] molecule has one nitrogen atom then [tex]1.369\times 6.022\times 10^{23}[/tex] number of molecules of [tex]NO_2[/tex] will contain [tex]1.369\times 6.022\times 10^{23}[/tex] number of nitrogen atoms
As per question number of Ni atoms is equal to the number of nitrogen atoms
Number of Ni atoms=[tex]1.369\times 6.022\times 10^{23}[/tex] atoms
Number of moles = [tex]\frac{1.369\times 6.022\times 10^{23}}{6.022\times 10^{23}}=1.369moles[/tex]
Mass of Nickel = [tex]Moles\times \text{Molecular mass}}[/tex]
Molecular mass of Nickel = 58.69 g/mol
Mass of nickel = [tex]1.369mol\times 58.69g/mol=80.346grams[/tex]
The mass of Ni that has as many atoms as there are N atoms in 63.0 g of NO2 is 80.75 g of Ni.
We have to find the number of moles of NO2 from;
Number of moles = mass/molar mass
Mass of NO2 = 63.0 g
Molar mass of NO2 = 46 g/mol
Number of moles = 63.0 g/46 g/mol
Number of moles = 1.37 moles
Number of nitrogen atoms in 63.0 g NO2 = 1 × 6.02 × 10^23 × 1.37 moles
= 8.24 × 10^23 atoms of Nitrogen
For the mass of Ni that has as many atoms as there are N atoms in 63.0 g of NO2;
1 mole of Ni contains 59 g of Ni
59 g of Ni contains 6.02 × 10^23
x g of Ni contains 8.24 × 10^23 atoms
x = 59 g × 8.24 × 10^23 atoms/6.02 × 10^23
x = 80.75 g of Ni
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