If DE=4x+10, EF =2x-1, and DF=9x-15, find DF

Answer:
Step-by-step explanation:
If DE = 4x+10,EF =2X -1, and DF= 9x - 15 find DF
(de + ef ) - df = 2e || 2e/2 = e || ed - e = d || ef - e = f || f + d = df
de + ef = 6x + 11 || (6x +11) - df = -3x -6 || 2e/2 = -3x/2 - 3 || (-3x/2 - 3) - de = x/2 + 7|| (- 3x/2 - 3) - ef = -x/2 - 1|| d + f = 6
Answer:
[tex]DF=201[/tex]
Step-by-step explanation:
We have been given that segment [tex]DE=4x+10[/tex], segment [tex]EF=2x-1[/tex] and [tex]DF=9x-15[/tex]
From the given information, we can set an equation as:
[tex]DF=DE+EF[/tex]
[tex]9x-15=4x+10+2x-1[/tex]
Combine like terms:
[tex]9x-15=6x+9[/tex]
[tex]9x-15+15=6x+9+15[/tex]
[tex]9x=6x+24[/tex]
[tex]9x-6x=6x-6x+24[/tex]
[tex]3x=24[/tex]
[tex]\frac{3x}{3}=\frac{24}{3}[/tex]
[tex]x=24[/tex]
[tex]DF=9x-15[/tex]
[tex]DF=9(24)-15[/tex]
[tex]DF=216-15[/tex]
[tex]DF=201[/tex]
Therefore, DF equals 201 units.