Gravitational force between two masses is given by formula
[tex]F = \frac{Gm_1m_2}{r^2}[/tex]
here we know that
[tex]m_1 = 55 kg[/tex]
[tex]m_2 = 1234 kg[/tex]
[tex]r = 3 m[/tex]
[tex]G = 6.67 \times 10^{-11} Nm^2/kg^2[/tex]
now from the above equation we will have
[tex]F = \frac{(6.67 \times 10^{-11})(55)(1234)}{3^2}[/tex]
[tex]F = 5.03 \times 10^{-7}N[/tex]
so above is the gravitational force between car and the person
From Newton's gravitational law, the force of gravity between you and the car is 5.03 x [tex]10^{-7}[/tex] Newton strong.
According to Newton, the force of attraction between two masses of directly proportional to the product of the masses and inversely proportional to the square of the distance between them. That is,
F = [tex]\frac{GMm}{r^{2} }[/tex]
From the question, the given parameters are
M = 1234 kg
m = 55 kg
r = 3 m
G = 6.67 x [tex]10^{-11}[/tex]N[tex]m^{2}kg^{-2}[/tex]
Substitute all the parameters into the formula
F = (6.67 x [tex]10^{-11}[/tex] x 1234 x 55) / [tex]3^{2}[/tex]
F = 4.527 x [tex]10^{-6}[/tex] / 9
F = 5.03 x [tex]10^{-7}[/tex] N
Therefore, the force of gravity between you and the car is 5.03 x [tex]10^{-7}[/tex]
Newton strong.
Learn more about Gravitational force here: https://brainly.com/question/2537310
