Respuesta :
You have velocity 1 of 5 km per hour after 1 hour and velocity 2 of 3 km per hour after 2 hours.
Part A)
Let Velocity = a +bt, with t being the time in hours.
For velocity 1 you have a +b = 5
For velocity 2, you have a + 2b =3
Now subtract velocity 1 from velocity 2:
a +2b - (a+b) = 3-5
Simplify to get b = -2
Now solve for a in the first equation:
a + b =5
Replace b with -2:
a - 2 = 5
a = 7
Now replace a and b in the original formula:
Velocity = 7 -2t
Part B)
Create a table with x and Y values to graph.
X axis would be the time and the velocity would be the Y axis
Your time would be 0 , 1, 2 3 and 4 hours.
Using the final equation from part A, replace t with the hours ans solve for the velocities, which become the y axis:
7 - 2(0) = 7-0 = 7
7 - 2(1) = 7-2 = 5
7 - 2(2) = 7-4 = 3
7 - 2(3) = 7-6 = 1
7-2(4) = 7-8 = -1
Now you have your x and y coordinates to plot on a graph:
(0,7) (1,5) (2,3) (3,1) and (4,-1)
Answer:
- A) 2x +y = 7
- B) see the attached graph
Step-by-step explanation:
Part A. Let x represent the number of hours after the runner starts; let y represent the velocity of the runner in km/h. You are given two points (x, y) = (1, 5) and (2, 3) and asked to write a standard form equation for a line through them.
It may be convenient to start with the form ...
... (y2 -y1)(x -x1) = (x2 -x1)(y -y1)
Filling in the given point values, this is ...
... (3-5)(x -1) = (2-1)(y -5)
... -2x +2 = y -5
... 2x +y = 7 . . . . . . add 5+2x to put into standard form
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Part B. You can plot the two points from Part A and draw the line through them to graph the equation of their line. You will note that the runner's velocity is predicted to be negative after 3.5 hours.
