Respuesta :
Answer:
Given the system of equations:
[tex]3x+y = 10[/tex] ...... (1)
[tex]y=x-2[/tex] ......(2)
Substitute the equation (2) into (1);
[tex]3x+x-2= 10[/tex]
Combine like terms;
4x-2 = 10
Add 2 to both sides we have;
4x= 12
Divide both sides by 4;
x = 3
Substitute in (2) to solve for y;
[tex]y=3-2=1[/tex]
⇒y = 1
Therefore, the ordered pair is, (3, 1).
Answer: x= 3 and y=1
Step-by-step explanation:
3x + y = 10 ------(1)
y = x - 2 ---------(2)
substitute equation(2) in equation (1)
3x + x - 2 =10
4x - 2 = 10
add 2 to bothside
4x - 2 +2 = 10+2
4x = 12
Divide bothside by 4
4x/4 = 12/4
x = 3
substitute x=3 in equation (1)
3x + y = 10
3(3) + y = 10
9 + y = 10
subtract y from bothside
9 + y - 9 = 10-9
y = 1
Therefore; x =3 and y=1
