Answer:
Answer (5):
[tex]y=\frac{2}{3}x+\frac{80}{3}[/tex]
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Answer (6):
y=-3x+140
Step-by-step explanation:
Answer (5):
Pick any two given data points from the graph say (20,40) and (50,60).
Now we will find equation of line passing through these two points.
Slope [tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{60-40}{50-20}=\frac{20}{30}=\frac{2}{3}[/tex]
Now plug the value of slope m=2/3 and any one point say (20,40) from above two points into formula y=mx+b
[tex]y=mx+b[/tex]
[tex]40=(\frac{2}{3})(20)+b[/tex]
[tex]40=\frac{40}{3}+b[/tex]
[tex]40-\frac{40}{3}=b[/tex]
[tex]\frac{80}{3}=b[/tex]
Now plug value of m and b into y=mx+b
Then final answer will be :
[tex]y=\frac{2}{3}x+\frac{80}{3}[/tex]
You can repeat exactly same process for problem number (6) using points say (30,50) and (40,20).
Then answer will be y=-3x+140
