The first orange paint mixture contains 3 parts red and 5 parts yellow. A second orange paint mixture contains 4 parts red and 6 parts yellow. Which of the following statements is true? The first paint mixture is yellower than the second paint mixture.

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ColinJacobus ColinJacobus · Answer 1 · 2019-01-17T12:04:07+01:00

Answer: The answer is (a) The first paint mixture is yellower than the second mixture.

Step-by-step explanation: Given that there are two orange mixtures as follows -

In the first mixture, there are 3 parts red and 5 parts yellow. So, the proportions of red and yellow are

[tex]r_1=\dfrac{3}{3+5}=\dfrac{3}{8}=0.375[/tex]

and

[tex]y_1=\dfrac{5}{3+5}=\dfrac{5}{8}=0.625.[/tex]

In the second mixture, there are 4 parts red and 6 parts yellow. So, the proportions are

[tex]r_2=\dfrac{4}{4+6}=\dfrac{4}{10}=0.4[/tex]

and

[tex]y_2=\dfrac{6}{4+6}=\dfrac{6}{10}=0.6.[/tex]W

Hence,

[tex]y_1>y_2,[/tex] i.e., the proportion of yellow in first mixture is more than in the second mixture.

Thus, the first mixture is yellower than the second mixture.