Answer:
None of these options has "no solution"
Step-by-step explanation:
we will verify each options
(1)
y = 4x and y = 2x - 3
we can set them equal and solve for x
[tex]4x=2x-3[/tex]
[tex]2x=-3[/tex]
[tex]x=-\frac{3}{2}[/tex]
Since, solutions exists
so, this is FALSE
(2)
y = -4x and y = 2x - 3
we can set them equal and solve for x
[tex]-4x=2x-3[/tex]
[tex]-6x=-3[/tex]
[tex]x=\frac{1}{2}[/tex]
Since, solutions exists
so, this is FALSE
(3)
y = 4x and y = 2x+ 3
we can set them equal and solve for x
[tex]4x=2x+3[/tex]
[tex]2x=3[/tex]
[tex]x=\frac{3}{2}[/tex]
Since, solutions exists
so, this is FALSE
(4)
y = -4-x and y = 2x - 3
we can set them equal and solve for x
[tex]-4-x=2x-3[/tex]
[tex]-3x=1[/tex]
[tex]x=-\frac{1}{3}[/tex]
Since, solutions exists
so, this is FALSE
So, No system of equations have no solution
