Answer:
110 Degrees
Step-by-step explanation:
1 / 3
A circumscribed angle is supplementary to the central angle that intercepts the same arc.
The reason is that ABOCABOCA, B, O, C is a quadrilateral, so its angles add up to 360^\circ360
∘
360, degrees. Each of the tangent angles, \angle B∠Bangle, B and \angle C∠Cangle, C, has a measure of 90^\circ90
∘
90, degrees.
\begin{aligned} \text{m}\angle B+ \text{m}\angle C+ \pink{\text{m}\angle A} + \blue{\text{m}\angle O} &= 360\\ 90 + 90 + \pink{\text{m}\angle A} + \blue{\text{m}\angle O} &= 360\\ \pink{\text{m}\angle A} + \blue{\text{m}\angle O} &= 180\\ \end{aligned}
m∠B+m∠C+m∠A+m∠O
90+90+m∠A+m∠O
m∠A+m∠O
=360
=360
=180
Hint #22 / 3
\pink{70^\circ} + \blue{\text{m}\angle O}= 180^\circ70
∘
+m∠O=180
∘
start color #ff00af, 70, degrees, end color #ff00af, plus, start color #6495ed, start text, m, end text, angle, O, end color #6495ed, equals, 180, degrees
Hint #33 / 3
\blue{\text{m}\angle O} = \blue{110^\circ}m∠O=110
∘
