Answer:
Option 1
Step-by-step explanation:
The point slope form of a line is [tex](y-y_1)=m(x-x_1)[/tex] where [tex]x_1=1\\y_1=2[/tex]. We write
[tex](y-2)=m(x-1)[/tex]
We know m the slope is parallel to the line. Since it is parallel, the slope must be the same so m is [tex]\frac{3}{2}[/tex] and we substitute.
[tex](y-2)=\frac{3}{2}(x-1)[/tex]
We can simplify the equation to slope intercept form.
[tex](y-2)=\frac{3}{2}(x-1)\\y-2=\frac{3}{2}x-\frac{3}{2}\\y-2+2=\frac{3}{2}x-\frac{3}{2}+2\\y=\frac{3}{2}x-\frac{1}{2}[/tex]
