Answer:
Mary have 90 flowers
Step-by-step explanation:
Given that Mary had flowers, of which 3/5 were roses and the rest were orchids.
Let Mary had x flowers.
∴ Roses are=[tex]\frac{3}{5} x[/tex]
and orchids are [tex]x-\frac{3}{5}x=\frac{2}{5}x[/tex]
Now, She sold 1/2 of the roses and 1/4 of the orchids. She then had 54 roses and orchids left.
Hence, total flowers i.e roses and orchids sold are [tex]\frac{1}{2}(\frac{3}{5}x)+\frac{1}{4}(\frac{2}{5}x)=\frac{4}{10}x=\frac{2}{5}x[/tex]
The flowers which left are [tex]x-\frac{2}{5}x=\frac{3}{5}x[/tex]
⇒[tex]\frac{3}{5}x=54[/tex]⇒[tex]x=90[/tex]
Therefore, Mary have 90 flowers
