Respuesta :

gmany

[tex]1)\\\dfrac{x}{6}=\dfrac{\not3^1}{\not9_3}\\\\\dfrac{x}{6}=\dfrac{1}{3}\qquad\text{multiply both sides by 6}\\\\x=\dfrac{1}{\not3_1}\cdot\not6^2\\\\\boxed{x=2}\\\\2)\\\dfrac{x}{8}=\dfrac{\not9^3}{12\!\!\!\!\!\diagup_4}\\\\\dfrac{x}{8}=\dfrac{3}{4}\qquad\text{multiply both sides by 8}\\\\x=\dfrac{3}{\not4_1}\cdot\not8^2}\\\\x=3\cdot2\\\\\boxed{x=6}[/tex]

[tex]3)\\\dfrac{x}{12}=\dfrac{\not3^1}{\not9_3}\\\\\dfrac{x}{12}=\dfrac{1}{3}\qquad\text{multiply both sides by 12}\\\\x=\dfrac{1}{\not3_1}\cdot12\!\!\!\!\!\diagup_4\\\\\boxed{x=4}\\\\4)\\\dfrac{x}{12}=\dfrac{\not6^3}{\not8_4}\\\\\dfrac{x}{12}=\dfrac{3}{4}\qquad\text{multiply both sides by 12}\\\\x=\dfrac{3}{\not4_1}\cdot12\!\!\!\!\!\diagup_3\\\\x=3\cdot3\\\\\boxed{x=9}[/tex]