Answer:
C₆H₆
Step-by-step explanation:
Data:
EF = CH
MF mass = 78.11 u
Calculations:
EF Mass = (12.01 + 1.008) u
EF Mass = 13.018 u
The molecular formula is an integral multiple of the empirical formula.
MF = (EF)ₙ
n = MF Mass/EF Mass
n = 78.11 u/13.02 u
n = 6.000 ≈ 6
MF = (CH)₆
MF = C₆H₆
The chemical formula of the compound has been [tex]\rm C_6H_6[/tex].
The empirical formula has been given as the whole number ratio of the elements in the compound. The chemical formula has been the representation of each atom constituted in the compound.
The empirical formula for the compound has been CH. The mass of empirical formula has been the sum of mass of C and H.
The mass of empirical formula has been:
[tex]\rm Empirical\;formula\;mass=C+H\\Empirical\;formula\;mass=12+1\\Empirical\;formula\;mass=13\;g[/tex]
The mass of empirical formula has been 13 g. The molar mass of compound has been 78.11 g/mol.
Number of empirical formula unit, (n) has been given as:
[tex]n=\dfrac{13}{78.11} \\n=6[/tex]
The number of empirical formula unit has been 6. Thus, the chemical formula of the compound has been:
[tex]\rm (CH)_6=C_6H_6[/tex]
The chemical formula of the compound has been [tex]\rm C_6H_6[/tex].
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