Respuesta :
Answer:- C = 82.66% and H = 17.34%
Solution:- To calculate the percentage composition we divide the mass of each atom in the molecule by the molar mass of the molecule and multiply by 100.
The given molecule is [tex]C_4H_1_0[/tex] . It has four carbons and 10 hydrogens. So, to get the mass of carbon we multiply the atomic mass of C by 4. Similarly to get the mass of hydrogen we multiply the atomic mass of H by 10.
mass of C = 4(12.01) = 48.04 g
mass of H = 10(1.008) = 10.08 g
Molar mass of molecule = 48.04 g + 10.08 g = 58.12 g
mass percentage of C = [tex](\frac{48.04}{58.12})100[/tex]
= 82.66%
mass percentage of H = [tex](\frac{10.08}{58.12})100[/tex]
= 17.34%
So, [tex]C_4H_1_0[/tex] has 82.66% carbon and 17.34% hydrogen by mass.
Answer: 82.7% C and 17.3% H
Explanation: you’re welcome :)
