Answer:
79 balls.
Step-by-step explanation:
We have been given that the weight of a basketball is normally distributed with a mean of 17 oz and a standard deviation of 2 oz.
Let us find the z-score for the weight 19 oz.
[tex]z=\frac{x-\mu}{\sigma}[/tex]
[tex]z=\frac{19-17}{2}[/tex]
[tex]z=\frac{2}{2}[/tex]
[tex]z=1[/tex]
Let us find P(z>1) using normal distribution table.
[tex]P(z>1)=1-0.84134[/tex]
[tex]P(z>1)=0.15866[/tex]
So the probability of a basketball having weight more than 19 oz is 0.15866. As there are 500 basketballs in the warehouse, so the total number of basketballs having a weight more than 19 oz will be:
[tex]\text{Total number of balls having weight more than 19 oz}=500\times 0.15866[/tex]
[tex]\text{Total number of balls having weight more than 19 oz}=79.33\approx 79[/tex]
Therefore, 79 balls weigh more than 19 oz.
