Respuesta :
Answer: [tex](\frac{41}{50})^{10}[/tex]
Step-by-step explanation:
Since, According to the question,
The chance of finding a bug in a program = 18%
Thus, the probability of finding the bug in first attempt = [tex]\frac{18}{100}=\frac{9}{50}[/tex]
⇒ The probability of not finding any bug in first attempt = [tex]1 - \frac{9}{50} =\frac{41}{50}[/tex]
Similarly, in second attempt , third attempt, fourth attempt_ _ _ _ _ tenth attempt, the probability of not finding any bug is also equal to [tex]\frac{41}{50}[/tex]
Thus, the probability that she does not find a bug within the first 10 programs she examines
= [tex]\frac{41}{50}\times \frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}[/tex]
= [tex](\frac{41}{50})^{10}[/tex]
Answer: 0.14
Step-by-step explanation:
The expert just didnt round the answer for you guys.
