Respuesta :
Answer with explanation:
Amount of money Possessed by Anna = $ 35
Money spent on ticket = $9.50
Money spent on Snacks = $ 3.50
Let x number of snacks, which will be least number of snacks that Anna can buy.
transforming the situation in terms of inequality
→9.50 +3.50 x≤ 35
→9.50 -9.50+3.50 x≤35-9.50
→3.50 x≤25.50
Dividing both sides by 3.50, we get
→x≤7.3(approx)
which can't be number of Snacks, as it will be an integral value.
So, minimum number of snacks with given amount of money = 7
So, Anna can buy snacks(x)={x:x≤7,x=1,2,3,4,5,6,7}=At most 7.
Answer:
7 is the maximum snacks Anna can buy.
Step-by-step explanation:
Anna is at the movie theater and has $35 to spend.
She spends $9.50 on a ticket. Money left now = [tex]35-9.50=25.50[/tex]
She wants to buy some snacks. Let the snacks count be x
Each snack costs $3.50. So, can buy 3.50x snacks
Now given inequality that represents this situation: [tex]9.50+3.50x \leq 35[/tex]
Solving this inequality we can find the number of snacks Anna can buy
[tex]3.50x\leq 25.50[/tex]
[tex]x\leq 7.2[/tex]
Rounding it to whole number we get 7.
So, Anna can buy a maximum of 7 snacks.
We can check the equation:
[tex]9.50+3.50(7)\leq 35[/tex]
[tex]9.50+24.50\leq 35[/tex]
[tex]34\leq 35[/tex]
Hence, 7 is the maximum snacks Anna can buy.
