Respuesta :
Answer: 0.58209 (approx)
Step-by-step explanation:
Let A is the event of a male employee stayed at least 3 years.
And, B is the event of a female employee stayed at least 1 year.
Then, According to the question,
P(A) = 0.20
P(B) = 0.67
Thus, [tex]P(A\cap B) = 0.20[/tex] ( because the one who having at least 3 years experience already having at least 1 year of experience.)
⇒ The probability that a male employee stayed at least 3 years given that they stayed 1 year = [tex]\frac{P(A\cap B)}{P(B)}[/tex]
= [tex]\frac{0.39}{0.67}[/tex]
= 0.58208955223 ≈ 0.58209
Answer:
0.298
Step-by-step explanation:
A company wanted to determine what percentage of its employees stayed for at least 1, 2, and 3 years.
The data they compiled is given below and covers 200 male employees and 300 female employees.
Male
1 year = 0.67
2 year = 0.45
3 year = 0.20
Female
1 year = 0.73
2 years = 0.64
3 years = 0.39.
Let A be the event that a male employee stayed at least 3 years
So,P(A) = 0.20
Let B be the event that they stayed 1 year
So, P(B) = 0.67
Now we are supposed to find the probability that a male employee stayed at least 3 years given that they stayed 1 year
So, the probability that a male employee stayed at least 3 years given that they stayed 1 year = [tex]\frac{0.20}{0.67}[/tex]
= [tex]0.298[/tex]
Hence the probability that a male employee stayed at least 3 years given that they stayed 1 year is 0.298.
