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please help me ive been crying for hours because im so stressed out

Write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the given equation.

1. (2, -2) ; y = -x - 2

a) y = -2x
b) y = 2x
c) y = 1/2 x
d) y = - x

2. (2, -1) ; y = - 3/2 x + 6

a) y=-3/2x+6
b) -3/2x+1
c) -3/2x-1x
d) -3/2x+4

3. (4, 2) ; x=-3

a) y=2
b) y=2x+4
c) y=4x
d) x=4

Write an equation in slope intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation.

4. (-2, 3) ; y=1/2x-1

a) y=1/2x+1
b) y=-2x-1
c) y=1/2x-1
4) y=-1/2x-1

Respuesta :

corinltm

Answer:

1.  y=-x

2. y=-3/2x-2

3. x=4

4. y=-2x-1

Step-by-step explanation:

slope intercept form is y=mx+b with mx being the slope and b being the y intercept

if its parallel it has to have the same slope.

perpendicular lines have the opposite slope and sign. so if its a whole number you put it over 1 and if its a fraction you switch the values in the numerator and denominator in addition to changing the sign. You keep the y intercept the same.


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