Answer: Yes, I do agree with the claim.
Step-by-step explanation: As shown in the attached figure, the participant walks a path of 21 miles at a speed of 3 miles/hour.
He started at point A and reached at point B after walking a distance of 'x' miles in some time. He takes another t hours to walk from point B to final point C. Distance from B to C is (21-x).
Therefore, we have for path BC
[tex]\textup{speed}=\dfrac{\textup{distance}}{\textup{time}}\\\\\Rightarrow 3=\dfrac{21-x}{t}\\\\\Rightarrow 3t=21-x\\\\\Rightarrow x=-3t+21,[/tex] which is a straight line with slope -3.
Thus, the participant's claim was absolutely correct and I completely agree with the claim.
Answer:
[tex]y=21-3h[/tex]
Yes, the participant is right.
Step-by-step explanation:
Let h be the number of hours.
We have been that a participant in a 21 mile walkathon walks at a steady rate of 3 miles per hour. Then distance traveled in h hours will be 3h.
As the remaining distance is decreasing with each passing hour, so the remaining distance will be initial distance minus the distance covered in h hours. We can represent this information as:
[tex]y=21-3h[/tex], where y represents miles left to walk.
Since we know that slope-intercept form of an equation is: [tex]y=mx+b[/tex], where,
m= Slope of the line.
b = y-intercept or initial value.
Upon comparing our equation with slope-intercept form of equation we can see that slope of our line is -3, therefore, the participant is right.
