Answer:
The linear equation is : y = -2000·x + 21000
Step-by-step explanation:
Let the time be denoted by x and the value of the car be denoted by y
After 3 years the value is 15000
[tex]\implies x_1 = 3\text{ and }y_1 = 15000[/tex]
So, point is (3,15000)
After 2 years the value is 11000
[tex]\implies x_2 = 2 + 3 = 5\text{ and }y_2 = 11000[/tex]
So, point is (5,11000)
Now, to find the linear equation we need to find the slope(m) of these two obtained points : (3,15000) and (5,11000)
[tex]m=\frac{y_2-y_1}{x_2-x_1}\\\\m=\frac{11000-15000}{5-3}\\\\m=-2000[/tex]
So, the required linear equation will be :
[tex]y-y_1=m\cdot (x-x_1)[/tex]
y -15000 = -2000·(x - 3)
⇒ y - 15000 = -2000·x + 6000
⇒ y = -2000·x + 21000