Given data:
mass of oil = 2 × 10¹⁴ kg,
charge (q) = 8 × 10⁻¹⁸ C
drop is stationery between two parallel plates
and plates are at a distance of (d) = 20 mm
= 0.020 m,
Calculate potential difference (V) = ?
We know that the potential difference
V = E.d Volts
Where
d = distance between plates in meters
E = electric field in N/C
= m.g/q
q = charge in coulombs
m = mass in kg
Lets find out
E = m.g/q N/C
= (2 × 10¹⁴ × 9.8)/ 8×10⁻¹⁸ N/C
= 2.45 ×10³² N/C
Now calculating V = E.d
= 2.45 ×10³² × 0.020
= 4.9 ×10³⁰ volts
The potential difference is 4.9 ×10³⁰ volts
