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I need help with this:



A big ship drops its anchor.


The variable ll models the anchor's elevation (in meters) relative to the water's surface tt seconds after the ship drops its anchor.


l=-2.4t+75l=−2.4t+75


What is the initial height of the anchor?

Respuesta :

JeanaShupp

Answer: 75 meters


Step-by-step explanation:

Given: The variable ll models the anchor's elevation (in meters) relative to the water's surface t seconds after the ship drops its anchor as

[tex]I=-2.4t+75[/tex]

To find the initial height, substitute t=0 in the equation, we get

[tex]\Rightarrow\ I=-2.4(0)+75[/tex]

[tex]\Rightarrow\ I=75[/tex]

Therefore, the initial height of the anchor = 75 meters .

Answer:

The answer is 75 meters.

Step-by-step explanation:

I= -2.4t + 75

I= -2.4(0) + 75

I= 0 + 75

I= 75 meters

I did it on Khan and it was correct.