Answer:
3/2 and -2
Step-by-step explanation:
The quadratic formula is [tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}[/tex]. Here a=2, b=1, and c=-6.
Substitute and you'll have:
[tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-1+/-\sqrt{1^2-4(2)(-6)} }{2(2)}=\frac{-1+/-\sqrt{1+48} }{4)}[/tex]
[tex]\frac{-1+/-\sqrt{1+48} }{4}=\frac{-1+/-\sqrt{49} }{4}=\frac{-1+/-7 }{4}= \frac{3}{2} , -2[/tex]
