Answer:
1) Option D - 36
2) Option C - 9
3) Option C- [tex]\frac{1}{4}[/tex]
Step-by-step explanation:
Given : Two dice are rolled and outcome is an even number and then an odd number.
To find :
1)Size of sample spaces
When two dice are rolled total no. of outcomes are [tex]6^2=36[/tex]
Therefore, Option D is correct - 36
2)Number of desired outcomes
Condition is first come even than odd on a dice
Favorable outcomes = (2,1),(4,1),(6,1),(2,3),(4,3),(6,3),(2,5),(4,5),(6,5)
Number of desired outcomes is 9
Therefore, Option C is correct- 9
3)P(first is even and second is odd)
Favorable outcomes = (2,1),(4,1),(6,1),(2,3),(4,3),(6,3),(2,5),(4,5),(6,5)
Total no. of outcomes = 36
[tex]Probability = \frac{Favorable outcome}{Total outcomes}[/tex]
[tex]Probability=\frac{9}{36}=\frac{1}{4}[/tex]
Therefore, Option C is correct -[tex]\frac{1}{4}[/tex]