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What is the probability of rolling an even number and then an odd number when rolling two number cubes?

Size of sample spaces = A)6 B)12 C)30 D)36

Number of desired outcomes = A)3 B)6 C)9 D)18

P(first is even and second is odd) = A)1/36 B)1/12 C)1/4 D)1/2

What is the probability of rolling an even number and then an odd number when rolling two number cubes Size of sample spaces A6 B12 C30 D36 Number of desired ou class=

Respuesta :

Answer:

1) Option D - 36

2) Option C - 9

3) Option C- [tex]\frac{1}{4}[/tex]

Step-by-step explanation:

Given : Two dice are rolled and outcome is an even number and then an odd number.

To find :

1)Size of sample spaces

When two dice are rolled total no. of outcomes are  [tex]6^2=36[/tex]

Therefore, Option D is correct - 36

2)Number of desired outcomes

Condition is first come even than odd on a dice

Favorable outcomes = (2,1),(4,1),(6,1),(2,3),(4,3),(6,3),(2,5),(4,5),(6,5)

Number of desired outcomes is 9

Therefore, Option C is correct- 9

3)P(first is even and second is odd)

Favorable outcomes =  (2,1),(4,1),(6,1),(2,3),(4,3),(6,3),(2,5),(4,5),(6,5)

Total no. of outcomes = 36

[tex]Probability = \frac{Favorable outcome}{Total outcomes}[/tex]

[tex]Probability=\frac{9}{36}=\frac{1}{4}[/tex]

Therefore, Option C is correct -[tex]\frac{1}{4}[/tex]


Answer:

•Size of sample spaces= 36.

•Number of desired outcomes=9.

•P(first is even and second is odd)=1/4.

•To hard ???- 1st answer is D. 2nd answer is C. 3rd answer is C.

•Still too hard ;-;???- 1st answer is 36. 2nd answer is 9. 3rd answer is 1/4.

This is the best I could help , hope this will get you a ✅.♡

Step-by-step explanation:

Just did it ^-^