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Express the product of 4.0 × 10-2 m and 8.1 × 102 m using the correct number of significant digits. A. 3.2 × 101 B. 3.24 × 101 C. 32.4 D. 30

Respuesta :

Explanation:

The given digits whose product has to be calculated are [tex]4.0 \times 10^{-2}m[/tex] and [tex]8.1 \times 10^{2}m[/tex].

The terms [tex]10^{-2}[/tex] and [tex]10^{2}[/tex] will be cancelled out. Therefore, product of  [tex]4.0 m \times 8.1 m[/tex] is [tex]32.4 m^{2}[/tex].

Hence, we can conclude that the correct number of significant digits for the product of [tex]4.0 \times 10^{-2}[/tex]m and [tex]8.1 \times 10^{2}[/tex]m is [tex]32.4 m^{2}[/tex].

Answer:

The correct answer is option  C.

Explanation:

Significant figures : The figures in a number which express the value of the magnitude of a quantity to a specific degree of an accuracy is known as significant digits.

[tex] 4.0\times 10^{-2} m\times 8.1\times 10^2 m[/tex]

Using identity = [tex]a^m\times a^n=a^{m+n}[/tex]

=[tex]4.0\times 8.1\times 10^{-2+2}[/tex]

[tex]=32.4 m^2[/tex]

There are three significant figures in the answer. Hence, correct answer is option  C.

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