As we know that restoring force on the block when it is connected to a spring is given as
[tex]F = -kx[/tex]
now we can say
[tex]F = ma = - kx[/tex]
now we will have
[tex]a = -\frac{k}{m} x[/tex]
now we can say that angular frequency of the motion is
[tex]\omega^2 = \frac{k}{m}[/tex]
[tex]\omega = \sqrt{\frac{k}{m}}[/tex]
[tex]\omega = \sqrt\frac{89}{1.52}}[/tex]
[tex]\omega = 7.65 rad/s[/tex]
now the frequency is given as
[tex]f = \frac{\omega}{2\pi} = \frac{7.65}{2\pi}[/tex]
[tex]f = 1.22 Hz[/tex]
