PLEASE HELP WILL GIVE BRAINIEST

1.

Which is the equation of the given line in ponit-slope form?

A. y + 4 = 9/8(x + 1)

B. y + 1 = 8/9(x + 4)

C. y + 1 = 8/7(x + 4)

y - 1 = 8/9(x - 4)


(SAME IMAGE FOR QUESTION 2)

2.

Write the equation of the line in standard form.

A. -8x + 9y = 23

B. -8x + 9y = -23

C. -8x + 7y = 25

D. -9x + 8y = -23

PLEASE HELP WILL GIVE BRAINIEST 1 Which is the equation of the given line in ponitslope form A y 4 98x 1 B y 1 89x 4 C y 1 87x 4 y 1 89x 4 SAME IMAGE FOR QUESTI class=

Respuesta :

Answer:

1. B

2. A[tex](y+1)=\frac{8}{9} (x+4)\\y+1=\frac{8}{9} x+\frac{8}{9} *4\\y+1=\frac{8}{9} x+\frac{32}{9}\\9*(y+1=\frac{8}{9} x+\frac{32}{9})\\9y+9=8x+32\\-8x+9y=32-9\\-8x+9y=23[/tex]

Step-by-step explanation:

The point slope form of a line is [tex](y-y_1)=m(x-x_1)[/tex] where [tex]x_1=-4\\y_1=-1[/tex]. We write

[tex](y--1)=m(x--4)\\(y+1)=m(x+4)[/tex]

To find m, count the slope from each marked point on the graph. Notice one is 1/2 so we will count by halves. The slope is 8/9

This means B is the point slope form. To convert to the standard form, it must be written as [tex]ax^2+by^2=c[/tex]. We convert using inverse operations.