Answer: 0.0211 moles of air are present inside the bottle
Explanation:
Volume of the bottle = 0.500 L
Standard Pressure exerted by the air = 1 atm
Temperature of bottle in which air is present = 15 °C= 288 K(0 °C = 273 K)
Assuming air inside the bottle is behaving ideally:
PV=nRT
[tex]1 atm\times 0.500 L=n\times 0.0820 L atm/mol K\times 288 K[/tex]
[tex]n=\frac{1 atm\times 0.500 L}{0.0820 L atm/mol K\times 288 K}[/tex]
n = 0.0211 moles
0.0211 moles of air are present inside the bottle
