Answer:
Product is :(y²+3y+7)×(8y²+y+1) = 8y^4 + 25y^3 + 60y² + 10y + 7
Step-by-step explanation:
We have given two equations:
y²+3y+7 and 8y²+y+1
Product of above two equations can be given as:
(y²+3y+7)×(8y²+y+1)
or (y².8y² + y².y + y².1) + (3y.8y² + 3y.y +3y.1)+(7.8y²+7.y+7.1)
or 8y^4 + y^3 +y² + 24y^3 + 3y² +3y + 56y² + 7y +7
or 8y^4 + 25y^3 + 60y² + 10y + 7 , this is the answer
Answer:
8y⁴+25y³+60y²+10y+7
Step-by-step explanation:
Given two functions
y²+3y+7 and 8y²+y+1
To take the product of both functions means multiplying both functions together.
(y²+3y+7)(8y²+y+1)
Opening up the bracket we have:
= 8y⁴+y³+y²+24y³+3y²+3y+56y²+7y+7
Collecting the like terms
= 8y⁴+y³+24y³+y²+3y²+56y²+3y+7y+7
Adding up the functions with the same degree and simplifying the expression will give;
= 8y⁴+25y³+60y²+10y+7
This gives the product of both functions
