Answer:
(2,1,-5)
Step-by-step explanation:
2x-y+z =-2
x+3y -z =10
x+2z =-8
Multiply the first equation by 3 so we can eliminate y
3*(2x-y+z) =-2*3
6x -3y +3z = -6
Add this to the second equation
6x -3y +3z = -6
x+ 3y -z =10
--------------------------
7x +2z =4
Multiply this equation by -1
-7x-2z = -4
Add the third equation
-7x-2z = -4
x+ 2z =-8
----------------
-6x = -12
Divide by -6
-6x/-6 = -12/-6
x = 2
Now we will find z
x+2z = -8
2+2z = -8
Subtract 2 from each side
2-2+2z= -8-2
2z=-10
Divide by 2
2z/2 = -10/2
z= -5
Now we need to find y
2x-y+z =-2
2(2) -y+-5=-2
4 -y-5 = -2
Combine like terms
-1 -y = -2
Add 1 to each side
-1+1 -y =-2+1
-y = -1
Multiply by -1
y = 1
x=2 y=1 z=-5
(2,1,-5)
