What’s the perimeter and area of the triangle above?

Hello from MrBillDoesMath!
Answer:
Perimeter = 18 cos(42) + 18 sin(42) + 18
Area = 162 * sin(42) cos(42)
Discussion:
x = 18 * cos(42) and y = 18 sin(42) so...
Perimeter = x + y + 18 =
18 cos(42) + 18 sin(42) + 18 which is approx
18 (.743) + 18 (.669) + 18 = 43.42
Area = (1/2) bh = (1/2) yx =
= (1/2) ( 18 sin(42)) (18 cos(42))
= (1/2) (18*18) sin(42) cos(42)
= (324/2) sin(42) cos(42)
= 162 * sin(42) cos(42)
which is approx
= 80.56
Thank you,
MrB