Answer:
Total surface area of triangular pyramid is 9600 square inches.
Step-by-step explanation:
Below figure shows the open pyramid having base with each edge 60 inches and the height of each triangular face is 50 inches.
We have to calculate the total surface area of this pyramid.
Total surface area of triangular pyramid = surface area of square base + surface area of 4 triangular faces.
Surface area of square = side × side
= 60 × 60
= 3600 square inches.
[tex]\text{surface area of a triangular face}=\frac{1}{2}\times \text{base} \times \text{height}[/tex]
[tex]\text{surface area of a triangular face}=\frac{1}{2}\times 60 \times 50[/tex]
[tex]\text{surface area of a triangular face}=30 \times 50[/tex]
[tex]\text{surface area of a triangular face}=1500[/tex]
⇒ surface area of a triangular face = 1500 square inches.
Thus, surface area of four triangular faces = 1500 ×4 square inches.
= 6000 square inches.
Total surface area of triangular pyramid = surface area of square base + surface area of 4 triangular faces.
= ( 3600 + 6000) square inches.
= 9600 square inches.
Thus, Total surface area of triangular pyramid is 9600 square inches.
