Answer:
The distance between foci is 60 feet
Step-by-step explanation:
we are given
a pond has a major axis of 68 feet
so, [tex]a=\frac{68}{2} =34[/tex]
a minor axis of 32 feet
so, [tex]b=\frac{32}{2} =16[/tex]
now, we know ellipse formula
[tex]c^2=a^2-b^2[/tex]
where
c is the distance between center and focus
so, we can plug it and find c
[tex]c^2=34^2-16^2[/tex]
[tex]c=30[/tex]
Distance between foci is
[tex]=2c[/tex]
[tex]=2\times 30[/tex]
[tex]=60[/tex]
