Line segment JM has endpoints with coordinates -2 and 14 on a number line. Points K and L are on segment JM. K has a coordinate of 2 and point L has a coordinate of 8. Find the probability that a point on JM is placed first on JL and a second point is not placed on KL.

5/8

25/64

8/15

15/64

please help
Anybody!!

Respuesta :

Answer:

B. [tex]\frac{25}{64}[/tex]

Step-by-step explanation:

Please find the attachment.  

We have been given that line segment JM has endpoints with coordinates -2 and 14 on a number line. Points K and L are on segment JM. K has a coordinate of 2 and point L has a coordinate of 8.

The probability that the first point is positioned on JL would be [tex]\frac{10}{16}[/tex] as there are total 10 points on JL as L is at point 8 and J is at point -2 so (8--2=8+2=10). Total number of points on the number line JM is (14--2=14+2=16)  

The probability that second point is not placed on KL would be:

[tex]P(\text{The point is not on KL)}=1-\text{probability that point is on KL}[/tex]

[tex]P(\text{The point is not on KL)}=1-\frac{\text{Total points on KL}}{\text{Total points on JM}} [/tex]

[tex]P(\text{The point is not on KL)}=1-\frac{(8-2)}{16} [/tex]

[tex]P(\text{The point is not on KL)}=1-\frac{6}{16} [/tex]

[tex]P(\text{The point is not on KL)}=\frac{16-6}{16} [/tex]

[tex]P(\text{The point is not on KL)}=\frac{10}{16} [/tex]

[tex]\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{10}{16}\times \frac{10}{16}[/tex]

[tex]\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{5}{8}\times \frac{5}{8}[/tex]

[tex]\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{25}{64}[/tex]

Therefore, our desired probability will [tex]\frac{25}{64}[/tex] and option B is the correct choice.

Ver imagen ApusApus

Answer: The answer is A. 15/64

Step-by-step explanation:

I got it right! Have a good day!